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Home/ Questions/Q 7892935
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T06:59:32+00:00 2026-06-03T06:59:32+00:00

I have some C+ arrays that I have built as follows: std:array<const char *,

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I have some C+ arrays that I have built as follows:

std:array<const char *, 4) test1 = {abc.c_str(), def.c_str(), ghi.c_str()};

where abc, def, ghi are std::string

I have to pass this array to another function which has the following prototype:
(int argc, char * argv[])

How should I modify array so that give non-const char* ot me that can be passed to above function. Or should I modify the function to const char*. I am not sure if the function tries to modify char* somewhere since this function code is not mine and not available as well currently.
But, in any case it would be good to ask how would I pass non-const char* array to the above function?

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  1. Editorial Team
    Editorial Team
    2026-06-03T06:59:33+00:00Added an answer on June 3, 2026 at 6:59 am

    This should work

    abc.append(1, 0); // guarantee NUL termination
    def.append(1, 0);
    ghi.append(1, 0);
    std:array<char *, 4> test1 = {abc.data(), def.data(), ghi.data()};
    

    or

    abc.append(1, 0);
    def.append(1, 0);
    ghi.append(1, 0);
    std:array<char *, 4> test1 = {&abc[0], &def[0], &ghi[0]};
    
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