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Home/ Questions/Q 8389365
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T18:42:27+00:00 2026-06-09T18:42:27+00:00

I have some class, like class object { public: virtual std::string name() const; };

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I have some class, like

class object {
public:
virtual std::string name() const; 
};

It provides some interface, and I want all derivated to override method name.
Problem is, it is not overriden, nothing breaks at compile time, but I get problems in run-time.
Is it any way to enforce method overriding?
EDIT: I want to enforce overriding in all derivates, not just direct descedants!

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  1. Editorial Team
    Editorial Team
    2026-06-09T18:42:29+00:00Added an answer on June 9, 2026 at 6:42 pm

    You can check whether a member is defined in a base class by checking its pointer-to-member type:

    static_assert(std::is_same<decltype(&U::name), std::string (U::*)()>::value,
                  "name must be defined directly in U");
    

    This does mean that at compile time you must have access to all the descendant types that you’re interested in.

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