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Home/ Questions/Q 7730647
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T06:16:41+00:00 2026-06-01T06:16:41+00:00

I have some class SimpleButton . It is a Child of Button class. Button

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I have some class SimpleButton. It is a Child of Button class. Button class has some method, which is overridden in SimpleButton. Now, if I whant to get access to this method from simpleButton, I just need to call [super someMethod]; But how to get access to it from outside of simpleButton? I tried:

SimpleButton *button;
[(Button*)button.superclass someMethod]; 

but this does not works…

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  1. Editorial Team
    Editorial Team
    2026-06-01T06:16:42+00:00Added an answer on June 1, 2026 at 6:16 am

    You can’t do it like that. If you’ve overridden a method in a subclass then you have changed the publicly available method of that class to be the one in your implementation. You would have to have a separate method which just calls the super implementation:

    Say you’ve overridden method foo. Create a new method, superFoo

    [button superFoo];
    

    Which internally does this:

    -(void)superFoo
    {
        [super foo];
    }
    

    However, if you need to do this sort of thing then you probably need to rethink why you have overridden the method in the first place. Perhaps you should have a new method on your subclass instead which does the unique parts and calls the super implementation itself, rather than overriding.

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