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Home/ Questions/Q 7525745
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T03:38:16+00:00 2026-05-30T03:38:16+00:00

I have some code: const string MY_STRINGS[3] = { A, B, C }; and

  • 0

I have some code:

const string MY_STRINGS[3] = { "A", "B", "C" };

and when I try to do this:

int main() {
  MY_STRINGS[1] = MY_STRINGS[2];
}

I get the following error:

Passing ‘const std::string’ as ‘this’ argument of ‘std::basic_string… & std::basic_string::operator= …’ discards qualifiers.

Sure. Makes sense. I can’t assign to a const string.

But when I do the following:

int main() {
  const string SOME_STRINGS[3] = MY_STRINGS;
  MY_STRINGS[1] = MY_STRINGS[2];
}

this compiles and works. What has changed, and why does it now compile?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T03:38:17+00:00Added an answer on May 30, 2026 at 3:38 am

    I believe GCC copies the array. Thus ensuring the const array is immutable and the variable array mutable.

    #include <string>
    #include <iostream>
    
    using namespace std;
    
    int main() {
        string varStrs[] = {"unchanged", "changed"};
        const string constStrs[2] = varStrs;
    
        varStrs[0] = varStrs[1];
        //constStrs[0] = constStrs[1]; // <-- will not compile
    
        cout << "const str: " << constStrs[0] << endl;
        cout << "var str: " << varStrs[0] << endl;
    
        return 0;
    }
    

    I tested this on GCC version 4.1.2

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