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Home/ Questions/Q 8388821
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T18:33:17+00:00 2026-06-09T18:33:17+00:00

I have some code like their example like so(untested as of yet)…. Promise<Object> promise

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I have some code like their example like so(untested as of yet)….

    Promise<Object> promise = new Promise<Object>();
    response.contentType = "application/json";
    JsonStreamer streamer = new JsonStreamer(columns, promise);
    while(streamer.hasMoreData()) {
          await(promise);
          response.writeChunk(streamer.nextDataChunk());
    }

What I don’t get is how do I release the socket that the client opened? I am streaming some very large data back in json. I need some kind of response.releaseSocket() after writing the last chunk. I see WebSockets has that but what about when I am using the await stuff?

thanks,
Dean

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  1. Editorial Team
    Editorial Team
    2026-06-09T18:33:18+00:00Added an answer on June 9, 2026 at 6:33 pm

    ah, I think it is noticing I never called await and in that case closes the socket. If I call await, it knows to keep the socket open. That makes sense.

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