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Home/ Questions/Q 388255
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T15:45:07+00:00 2026-05-12T15:45:07+00:00

I have some code like: try: do_the_first_part() except SomeError: do_the_next_part() I get an error

  • 0

I have some code like:

try:
    do_the_first_part()
except SomeError:
do_the_next_part()

I get an error that says "expected an indented block" – but I don’t want to write anything inside my except block, I just want it to catch and swallow the exception. How can I do this in Python?


See also: How to use "pass" statement?

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  1. Editorial Team
    Editorial Team
    2026-05-12T15:45:07+00:00Added an answer on May 12, 2026 at 3:45 pm

    Just write

    pass
    

    as in

    try:
        # Do something illegal.
        ...
    except:
        # Pretend nothing happened.
        pass
    

    EDIT: @swillden brings up a good point, viz., this is a terrible idea in general. You should, at the least, say

    except TypeError, DivideByZeroError:
    

    or whatever kinds of errors you want to handle. Otherwise you can mask bigger problems.

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