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Home/ Questions/Q 7746489
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T10:17:28+00:00 2026-06-01T10:17:28+00:00

I have some code that currently checks for minimum and maximum lentgh. I want

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I have some code that currently checks for minimum and maximum lentgh. I want to also require uppercase, lowercase, special char, and numeric. Any suggestions on what to add to this or where I can find some examples? I’ve been Googling and looking thru this forum and have been trying to add the additional password requirments and have been unsuccessful.

This is what I want to require.

At least eight characters in length
No more than 20 characters in length
at least lower-case letter and one upper-case
at least one special character from: !@#$%^&*()~`-=_+[]{}|:”;’,./<>?
at least one number [0-9] character
Cannot match the account login name or email address

My current password validation code

public static final int MIN_PASSWORD_LENGTH = 8;
public static final int MAX_PASSWORD_LENGTH = 20;

public static boolean isAcceptablePassword(String password)
{
    if(TextUtils.isEmpty(password))
        return false;

    int len = password.length();

    if(len < MIN_PASSWORD_LENGTH || len > MAX_PASSWORD_LENGTH)
        return false;

    for(int i = 0; i < len; i++)
    {
        char c = password.charAt(i);
        if (Character.isWhitespace(c))
            return false;
    }

    return true;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T10:17:29+00:00Added an answer on June 1, 2026 at 10:17 am

    When you’re analyzing String data, you should erase the whitespaces on the right and left. This is done by the Strimg#trim function like this:

    password = password.trim();
    

    To analize every character of the String, you can transform it to a char array, so it will be easier to fulfill your requirements:

    char[] arrPassword = password.toCharArray();
    

    Now you can evaluate a char using these functions: Character#isUpperCase, Character#isLowerCase, Character#isDigit.

    Last but not least, you can have a String with the special characters you need to check, and check if the actual character you’re evaluating is inside that String. This could be achieved using String#indexOf and String#valueOf, this las one to convert the char to a String type.

    Here is a code sample for all this explanation:

    public static final String SPECIAL_CHARACTERS = "!@#$%^&*()~`-=_+[]{}|:\";',./<>?";
    public static final int MIN_PASSWORD_LENGTH = 8;
    public static final int MAX_PASSWORD_LENGTH = 20;
    
    public static boolean isAcceptablePassword(String password) {
        if (TextUtils.isEmpty(password)) {
            System.out.println("empty string.");
            return false;
        }
        password = password.trim();
        int len = password.length();
        if(len < MIN_PASSWORD_LENGTH || len > MAX_PASSWORD_LENGTH) {
            System.out.println("wrong size, it must have at least 8 characters and less than 20.");
            return false;
        }
        char[] aC = password.toCharArray();
        for(char c : aC) {
            if (Character.isUpperCase(c)) {
                System.out.println(c + " is uppercase.");
            } else
            if (Character.isLowerCase(c)) {
                System.out.println(c + " is lowercase.");
            } else
            if (Character.isDigit(c)) {
                System.out.println(c + " is digit.");
            } else
            if (SPECIAL_CHARACTERS.indexOf(String.valueOf(c)) >= 0) {
                System.out.println(c + " is valid symbol.");
            } else {
                System.out.println(c + " is an invalid character in the password.");
                return false;
            }
        }
        return true;
    }
    

    The System.out.println(c + " is an invalid character in the password."); sentence is just to check the result of analyze the actual character.

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