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Home/ Questions/Q 369889
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T13:57:53+00:00 2026-05-12T13:57:53+00:00

I have some code that does this: function A(){ $.ajax({ …blah blah… success: function(data){

  • 0

I have some code that does this:

function A(){
    $.ajax({
        ...blah blah...
        success: function(data){
            return data;
    });
 }

and then I’m trying to use the data later:

var x = A();
x.doSomething();

but x is never stored, since A() takes a while. Is there any way to avoid this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T13:57:53+00:00Added an answer on May 12, 2026 at 1:57 pm

    Other Questions about the same topic:

    • Promote callback onSuccess return value to the Caller Function return value
    • How does one return data to the original caller function in Javascript?

    I’m sure there are more. However the advice in all of them will boil down to two paths to take.

    Pass a callback down the line

    function A(callback){
        $.ajax({
            //...blah blah...
            success: function(data){
              if (typeof callback == 'function') callback(data);
            }
        });
     }
    
     // passing our function through will cause it to be called after the data
     // is received
     A(function(data) {
      data.doSomething();
     }); 
    

    Making your AJAX Synchronous

    This option seems easier, but it will also block all script execution while it waits for your AJAX request, and therefore is not as desireable

    function A() {
      var retValue;
      $.ajax({
        async: false,
        success: function(data){ 
          retValue = data;
        }
      });
      return retValue;
    }
    
    var x = A();
    x.doSomething();
    
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