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Home/ Questions/Q 6186169
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T01:50:23+00:00 2026-05-24T01:50:23+00:00

I have some code that grabs some rows from a table and I want

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I have some code that grabs some rows from a table and I want to make an associative array in PHP that will be like [row_id] => row_title. This will then be used to populate a select list. The problem is, the key, unless I include a string in it, always reverts to an ordered number starting with 0. If I add a string in with the key, then the key retains the ID that I want. But obviously I don’t want the string in the key.

Here’s my code:

public static function select_array(){
    $courses = ORM::factory('course')->order_by('title')->find_all();
    $out = array();
    foreach($courses as $c){
        $out[$c->id] =  $c->title;
    }
    return $out;
}

The $c->id should be the id from the database, but PHP is overriding this with a count number. If I do this:

public static function select_array(){
    $courses = ORM::factory('course')->order_by('title')->find_all();
    $out = array();
    foreach($courses as $c){
        $test = "." . $c->id;
        $out[$test] =  $c->title;
    }
    return $out;
}

Then the key will include the correct ID, but with a “.” in front… I’ve tried using (string)$c->id but no luck with that either. I’ve also tried setting $test as ” ” . $c->id and then trimming it, but that doesn’t work, and it’s just a weird hacky attempt anyway.

Hope that makes sense. My question: How to simply tell the key to be a specific number?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T01:50:23+00:00Added an answer on May 24, 2026 at 1:50 am

    Can you var_dump $courses before the foreach statement and $out before the return?

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