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Home/ Questions/Q 9268295
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T14:46:29+00:00 2026-06-18T14:46:29+00:00

I have some code that looks like this: public Tuple<bool, SomeObjectModel> CheckIfJsonIsValid(string IncomingJson) {

  • 0

I have some code that looks like this:

public Tuple<bool, SomeObjectModel> CheckIfJsonIsValid(string IncomingJson)
{
   SomeObjectModel TheObjectModel = new SomeObjectModel();
   JavascriptSerializer TheSerializer = new JavascriptSerializer();
   .....

   try
   {
       TheObjectModel = TheSerializer.Deserialize<SomeObjectModel>(IncomingJson);
   }
   catch
   {
       return new Tuple<bool, SomeObjectModel>(false, null); //question here
   }

   .....
   return new Tuple<bool, SomeObjectModel>(true, TheObjectModel);
}

The calling method first check the returning tuple’s Item1, and if it’s false, ends its process.

Is it better practice a) to return a null value in the Tuple or b) to return a new and fresh instance of SomeObjectModel? Are there any performance implications?

Thanks for your suggestions.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T14:46:30+00:00Added an answer on June 18, 2026 at 2:46 pm

    Let me suggest three alternative solutions:


    ParseJsonIfValid: If deserializing works, TheObjectModel is always non-null. Thus, there is no need for the boolean:

    public SomeObjectModel ParseJsonIfValid(string IncomingJson)
    {
       JavascriptSerializer TheSerializer = new JavascriptSerializer();
       .....
    
       try
       {
           return TheSerializer.Deserialize<SomeObjectModel>(IncomingJson);
       }
       catch
       {
           return null;
       }
    }
    

    In the calling function simply check whether the return value is null or not.


    ParseJson: If the JSON is usually valid, and invalid JSON is a sign of something gone terribly wrong, just throw an exception:

    public SomeObjectModel ParseJson(string IncomingJson)
    {
       JavascriptSerializer TheSerializer = new JavascriptSerializer();
       .....
    
       try
       {
           return TheSerializer.Deserialize<SomeObjectModel>(IncomingJson);
       }
       catch (Exception e)
       {
           throw new TheServerSentRubbishException(e);
       }
    }
    

    Be sure to include the inner (“real”) exception, so that the calling function can log the real cause of the error for debugging purposes.


    TryParseJson: If null can be a valid deserialization, you can use the following pattern, which has the advantage of being consistent with the TryParse methods of the .NET framework:

    public bool TryParseJson(string IncomingJson, out SomeObjectModel theObjectModel)
    {
       JavascriptSerializer TheSerializer = new JavascriptSerializer();
       .....
    
       try
       {
           theObjectModel = TheSerializer.Deserialize<SomeObjectModel>(IncomingJson);
           return true;
       }
       catch (Exception e)
       {
           return false;
       }
    }
    
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