Question

I have some code that outputs like this:

void exec_prompt(char * usr_name, char * host_name)
{
    printf(" %s::%s\n", usr_name, host_name);
    return;
}

But the print out doesnt look as expected:

 geisst::ALPHA-DT2

There is that space at the front of the string.

The usr_name variable is passed from the main function and is returned from the getenv() function. The host_name variable is passed from the main function with the use of the following function:

char * returnHost()
{
    char hostname[1024];
    hostname[1023] = '\0';
    gethostname(hostname, 1023);

    return hostname;
}

Maybe the getenv() function adds a space?

Any help or advice is appreciated and please be nice 😛

GeissT

Answer 1

The reason is that your format has a space: ” %s::%s\n”

Just change it to:

printf("%s::%s\n", usr_name, host_name);