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Home/ Questions/Q 8908557
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T03:12:40+00:00 2026-06-15T03:12:40+00:00

I have some code to display the first ten characters of a string on

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I have some code to display the first ten characters of a string on a button. but I get the out of boiunds exception error when the string is less than 10 characters or null.

I thought a simple IF statement would fix it, but it doesn’t seem to have. Could someone point out my problem? Thanks

I checked with the android developers reference, and it doesn’t state a way to get around this

Button item1 = (Button) findViewById(R.id.buttontext1);
String ellipsed = PrefConnector.readString(this, PrefConnector.ONE, null);

if(ellipsed.length() < 1) ellipsed = "Touch to edit";
if(ellipsed.length() > 10) ellipsed = ellipsed.substring(0, 10) + "...";

item1.setText(ellipsed);
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  1. Editorial Team
    Editorial Team
    2026-06-15T03:12:41+00:00Added an answer on June 15, 2026 at 3:12 am

    If you’re getting a null-pointer exception, then there must be cases where ellipsed is null.

    Even if ellipsed is never null, your code above has a problem: If ellipsed.length()<10, you change it to “Touch to edit”, but then you check for length>10, and “Touch to edit”.length()>10, so short strings would always end up “Touch to e…”

    In any case, I think what you want to say is

    if (ellipsed==null || ellipsed.length()==0)
      ellipsed="Touch to edit";
    else if (ellipsed.length()>10)
      ellipsed=ellipsed.substring(0,10)+"...";
    
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