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Home/ Questions/Q 606083
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T17:12:59+00:00 2026-05-13T17:12:59+00:00

i have some code(inline assembly). void NativeLoop() { int m; __asm { PUSH ECX

  • 0

i have some code(inline assembly).

void NativeLoop()
{
    int m;
    __asm
    {
        PUSH ECX
        PUSH EDX
        MOV  ECX, 100000000
NEXTLOOP:
        MOV  EDX, ECX
        AND  EDX, 0X7FFFFFFF
        MOV  DWORD PTR m, EDX
        DEC  ECX
        JNZ  NEXTLOOP
        POP  EDX
        POP  ECX
    }
}

MS C++ Automagicaly adds these codes(marked with **) to my procedure.
Why?
how to avoid it?

  **push        ebp  
  **mov         ebp,esp 
  **push        ecx  
  push        ecx  
  push        edx  
  mov         ecx,5F5E100h 
NEXTLOOP:
  mov         edx,ecx 
  and         edx,7FFFFFFFh 
  mov         dword ptr m,edx 
  dec         ecx  
  jnz         NEXTLOOP
  pop         edx  
  pop         ecx  
  **mov         esp,ebp 
  **pop         ebp  
  **ret
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T17:12:59+00:00Added an answer on May 13, 2026 at 5:12 pm

    It is the standard function entry and exit code. It establishes and tears down the stack frame. If you don’t want it you can use __declspec(naked). Don’t forget to include the RET if you do.

    However, your snippet relies on a valid stack frame, your “m” variable requires it. It is addressed at [ebp-10]. Without the preamble, the ebp register won’t be set correctly and you’ll corrupt the stack frame of the caller.

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