Question

I have some confusion in how following expression works.

cc file_name.c  && ./a.out 

When filename.c gets compiled successfully , its exist status would be 0 (zero).
So as per logical && operation , second expression ( ./a.out ) not suppose to be executed.
But it still works and gives me result. How it works ?

Thanks

Answer 1

0 means success in the shell. It’s not the same as in C. From the bash man page:

AND and OR lists are sequences of one of more pipelines separated by the && and ││ control operators, respectively. AND and OR lists are executed with left associativity. An AND list has the form

command1 && command2

command2 is executed if, and only if, command1 returns an exit status of zero.