Question

I have some paths like this:

/www/site1.dev/public_html/test.htm
/www/site2.dev/html/test.htm
/www/site3.dev/public/test.htm

I’d like to pass them to a bash script and get a result back in this format:

http://site1.dev/test.htm
http://site2.dev/test.htm
http://site3.dev/test.htm

I’m not sure what the best way to handle the regex part of this is:

#!/bin/sh

RET='';

function trim() { echo $1; }


for ARG in "$@"
    do
        //do match and add existing RET value
        RET= 'http://'(regular expression or find/replace here) RET 
done


echo ">>$(trim $RET)<<"

Solution

My code based on Wes Hardaker’s answer

        DOMAIN=`echo $ARG | sed 's#.*www/##'`
        DOMAIN=`echo $DOMAIN | sed -E 's#/(public|html).*##'`
        POST=`echo $ARG | sed -E 's#.*html##'`
        echo 'http://'$DOMAIN$POST

Answer 1

The easiest way is probably to use ‘sed’. IE:

RET="http://"`echo $ARG | sed 's#/www##;s#/(public_|)html/#/#;'