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Home/ Questions/Q 3594326
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T19:41:55+00:00 2026-05-18T19:41:55+00:00

I have some problems with finding and replacing words in PHP files, especially when

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I have some problems with finding and replacing words in PHP files, especially when there is tons of them. So I thought that I will try to use javascript / jQuery.
I’d like to create table witch word_to_replace@new_word to do so.
This is my code which doesn’t work (and runs very long), filter doesn’t seem to work,
any advices?

 (function($){
    var arr = [ 'photo-board.pl przyjazny portal fotograficzny@ ','Upload images from your@Upload zdjęć z ',
      'Total number of images@ Całkowita liczba zdjęć'];
    for(var i in arr)
    {
       var st_to_replace = arr[i].split('@')[0];
      // alert(st_to_replace);
      $('*').filter(function() {
        return $(this).text() == st_to_replace;
        }).html(arr[i].split('@')[1]);
    }
    }) (jQuery)
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  1. Editorial Team
    Editorial Team
    2026-05-18T19:41:55+00:00Added an answer on May 18, 2026 at 7:41 pm

    You’re getting the text() of every page element (which will include the text of child elements) and replacing within it. That means, when you get the ‘body’ element you replace all the text, and then you get all the elements within body, and replace all the text, etc.

    Something like this may work better:

    (function($){
      var arr = [ 'photo-board.pl przyjazny portal fotograficzny@ ','Upload images from your@Upload zdjęć z ',
      'Total number of images@ Całkowita liczba zdjęć'];
      var bodyText = $('body').html();
      $.each(arr, function(i, v) {
        var words = v.split('@');
        var fromTxt = words[0], toTxt = words[1];
        bodyText = bodyText.replace(fromTxt, toTxt);
      });
      $('body').html(bodyText);
    })(jQuery);
    

    Demo here.

    It’s worth noting though that since this destroys and recreates the entire body content, you’ll loose event handlers and data set using .data(...).

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