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Editorial Team
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Asked: 2026-05-24T08:53:32+00:00

I have some records with that come with a prefix and suffix (may or

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I have some records with that come with a prefix and suffix (may or may not come).
I’m trying to figure the REGEXP_REPLACE that will always return me a parametrized value.

My attempt so far is:

with teste as (
select '+123145@domain.com' as num from dual
union
select '0054321@domain.com' as num from dual
union
select '006789' as num from dual
union
select '+9876' as num from dual
union
select '13579@domain.com' as num from dual
union
select '123456789' as num from dual
)
select REGEXP_REPLACE(num,'^00(.*)\@.*$|^\+(.*)\@.*$','\1') from teste

but is not quite there.

The output of that should be:

num
12345
54321
6789
9876
13579
123456789
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1 Answer

  1. Editorial Team

    Try this one here

    REGEXP_REPLACE(num,'^(00|\+)?(\d*)(\@.*)?$','\2')

    See it here online at Regexr

    I am not sure what Oracle regex is able to do. Critical points could be the \d meaning a digit, if this is not working replace \d with [0-9].

    (?:) are non capturing groups. The pattern inside is not stored in a capturing group so you can always replace with the first capturing group \1

    I also changed from your alternatives using | to optional parts using ? after the non capturing groups. The two brackets in your “OR” caused that the result is sometimes in group 1 (when the first alternative is matching) and sometimes in group 2 (when the second alternative is matching)

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