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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T20:10:34+00:00 2026-05-11T20:10:34+00:00

I have some very simple sample code like this: $.ajax({ url: ‘demo2.htm’, success: function(loadeddata){

  • 0

I have some very simple sample code like this:

$.ajax({
  url: 'demo2.htm',
  success: function(loadeddata){
    $("#loaded_data").after(loadeddata);
    alert('success');
  },
  error: function(){
    alert('failure');
  }
});

Loaded data currently returns everything. What I need to is to get only a specific div and after it add it to #loaded_data.

How do I do that?

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-11T20:10:34+00:00Added an answer on May 11, 2026 at 8:10 pm

    This is how jQuery does it internally:

    $("<div/>").append(loadeddata).find('#mydiv');
    

    If you expect to have SCRIPT tags in the HTML, you should throw this in to avoid any ‘Permission Denied’ errors in IE:

    $("<div/>").append(loadeddata.replace(/<script(.|\s)*?\/script>/g, "")).find('#mydiv');
    

    EDIT:

    You are missing the point of what is supposed to be happening.

    By doing $("<div/>").append(...); jQuery creates a dummy <div> and gets the browser to parse the HTML by inserting it inside of the <div>. Once that’s done, we can find the DIV we want, and return the HTML. So the more proper code sample I should have put above looks like this:

    var html = $("<div/>").append(loadeddata).find('#mydiv').html();
    $('#whereIwantIt').html(html);
    

    As you can see in the link, this does what you want.

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