Question

I have some well-behaved xml files I want to reformat (NOT PARSE!) using regex. The goal is to have every <trkpt> pairs as oneliners.

The following code works, but I’d like to get the operations performed in a single regex substitution instead of the loop, so that I don’t need to concatenate the strings back.

import re

xml = """
    <trkseg>
      <trkpt lon="-51.2220657617" lat="-30.1072524581">
        <time>2012-08-25T10:20:44Z</time>
        <ele>0</ele>
      </trkpt>
      <trkpt lon="-51.2220657617" lat="-30.1072524581">
        <time>2012-08-25T10:20:44Z</time>
        <ele>0</ele>
      </trkpt>
      <trkpt lon="-51.2220657617" lat="-30.1072524581">
        <time>2012-08-25T10:20:44Z</time>
        <ele>0</ele>
      </trkpt>
    </trkseg>
"""

for trkpt in re.findall('<trkpt.*?</trkpt>', xml, re.DOTALL):
    print re.sub('>\s*<', '><', trkpt, re.DOTALL)

An answer using sed would also be welcome.

Thanks for reading

Answer 1

How about this:

>>> regex = re.compile(
    r"""\n[ \t]*  # Match a newline plus following whitespace
    (?=           # only if... 
     (?:          # ...the following can be matched:
      (?!<trkpt)  #  (unless an opening <trkpt> tag occurs first)
      .           #  any character
     )*           # any number of times,
     </trkpt>     # followed by a closing </trkpt> tag
    )             # End of lookahead""", 
    re.DOTALL | re.VERBOSE)
>>> print regex.sub("", xml)

    <trkseg>
      <trkpt lon="-51.2220657617" lat="-30.1072524581"><time>2012-08-25T10:20:44Z</time><ele>0</ele></trkpt>
      <trkpt lon="-51.2220657617" lat="-30.1072524581"><time>2012-08-25T10:20:44Z</time><ele>0</ele></trkpt>
      <trkpt lon="-51.2220657617" lat="-30.1072524581"><time>2012-08-25T10:20:44Z</time><ele>0</ele></trkpt>
    </trkseg>