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Home/ Questions/Q 6909433
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T08:41:19+00:00 2026-05-27T08:41:19+00:00

I have something like: function init(){ $(‘.btn’).click(function(){ //do something; } } And when new

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I have something like:

function init(){
  $('.btn').click(function(){
    //do something;
  }
}

And when new content is added via ajax, I’m calling init(), so that click event applies to new buttons. But when I click it once, it captures several clicks (as many times as I called init()). It makes sense, but how to avoid it?

jsFiddle link: http://jsfiddle.net/s2ZAz/8/

Solutions:
* Use $.delegate() – http://api.jquery.com/delegate/
* Use $.live() – http://api.jquery.com/live/

Less preferred, but still, solutions:
* Use $.off() – http://api.jquery.com/off/ or $.unbind() – http://api.jquery.com/unbind/

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T08:41:20+00:00Added an answer on May 27, 2026 at 8:41 am

    click says, “for every object matching the selector, hook up this click listener”. You probably want something more like delegate that says “for every object that will ever match this selector, hook up this listener”.

    $(document).delegate('button', 'click', function() {
    });
    

    You will still get double callbacks if you call init twice, but in this manner, you won’t have to call init twice, because as new objects are added, they’ll already be assigned to click listeners.

    Note that document above should be replaced with the nearest persistent ancestor, as per Greg’s comment below.

    Demo.

    Since jQuery 1.7, you can preferably use the .on() function to achieve the same effect.

    Demo.

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