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Home/ Questions/Q 8169285
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T20:47:49+00:00 2026-06-06T20:47:49+00:00

I have something like solutions := solve ( {eqn1=0, eqn2=0, eqn3=0, eqn4=0, … }

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I have something like

solutions := solve ( {eqn1=0, eqn2=0, eqn3=0, eqn4=0, ... } )

which returns something like:

solutions := {Ax = -.2312688085, Ay = -7.770329620, Bx = -19.76873119, ....}

How can I access and save each solution?
Is “Ax := solutions[1];”, and so on, the only way?

Although solutions[1] doesn’t access to -.2312688085 in the above example, but a kind of string “Ax = -.2312688085”, so I end up having “Ax := Ax = -.2312688085”

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  1. Editorial Team
    Editorial Team
    2026-06-06T20:47:51+00:00Added an answer on June 6, 2026 at 8:47 pm

    The eval command allows you to use the solution just as if Ax,Ay,etc had been assigned, when evaluating other expressions involving those names. You get this effect without having to actually make the assignments (a benefit of which is that you can then create other equations in those variables without having to unassign their names).

    An alternative approach is to use assign command to actually make assignments of the returned numeric values to those variable names. But this makes subsequent attempts to use those symbolic variables names more awkward — you’d have to first unassign them. You might not want to get into a awkward pattern of having to assign/unassign over and over.

    Using eval is easier, I think. But you can try both, of course, and use what you prefer.

    Some examples might help:

    restart:
    
    eq1 := Ax + Ay + 8.001598428:
    eq2 := Bx + 20.08373119:
    eq3 := By + Ay + 8.085329620:
    eq4 := By + 0.315:
    
    solutions := solve([eq1=0, eq2=0, eq3=0, eq4=0]);
    
        {Ax = -0.2312688080, Ay = -7.770329620, Bx = -20.08373119, 
         By = -0.3150000000}
    
    eval(Ax, solutions);
    
                         -0.2312688080
    
    eval(Ax^2 + sin(By), solutions);
    
                         -0.2563312096
    
    eq5 := cos(Bx) + sin(Ax);   # still convenient
    
                       cos(Bx) + sin(Ax)
    
    restart:
    
    eq1 := Ax + Ay + 8.001598428:
    eq2 := Bx + 20.08373119:
    eq3 := By + Ay + 8.085329620:
    eq4 := By + 0.315:
    
    solutions := solve([eq1=0, eq2=0, eq3=0, eq4=0]);
    
      {Ax = -0.2312688080, Ay = -7.770329620, Bx = -20.08373119, 
       By = -0.3150000000}
    
    assign(solutions);
    
    Ax;
    
                         -0.2312688080
    
    Ax^2 + sin(By);
    
                         -0.2563312096
    
    eq5 := cos(Bx) + sin(Ax); # oops
    
                          0.1010869460
    
    unassign('Ax'):
    unassign('Bx'):
    
    eq5 := cos(Bx) + sin(Ax);
    
                       cos(Bx) + sin(Ax)
    
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