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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:08:41+00:00 2026-05-13T18:08:41+00:00

I have something like this going on in my Java program: void f(Object o)

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I have something like this going on in my Java program:

void f(Object o) {
    g(o);
}

<T extends MySuperClass & MyInterface> void g(T x) {
    ...;
}

How can I cast o so that this works? There seems to be no way to specify both a base class and an interface in variable declarations without using generics. I don’t think generics will work here, because o is being created dynamically using reflection, so its actual class is not known at compile time.

(Yeah, I know this is a weird thing to want to do. But I actually do need functionality from both the superclass and the interface. I guess I could do all of the type checking at runtime with instanceof, but that just seems so Java 1.4…)

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:08:41+00:00Added an answer on May 13, 2026 at 6:08 pm

    It seems to be there is no way to invoke a “raw” generic method. But you can create an object of raw type (the following conversion is, obviously, unsafe):

    void f(Object o) {
        Caster<?> c = new Caster(); 
        g(c.cast(o)); 
    }
    
    class Caster<T extends MySuperClass & MyInterface> {
        public T cast(Object o) {
            return (T) o;
        }
    }
    
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