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Asked: 2026-05-10T21:36:21+00:00

I have something like this: <node TEXT= txt A /> <node TEXT= txt X

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I have something like this:

<node TEXT='   txt A   '/> <node TEXT='         txt X  '/> <node>    <html>       <p>         txt Y       </p>    </html> </node> <node TEXT='txt B'/>

and i want to use XSLT to get this:

txt A txt X txt Y txt B

I want to strip all useless whitespaces and linebreaks of @TEXT’s and CDATA’s. The only XML-input that is giving structure to the output are the <node>-tags.

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1 Answer

  1. The following transformation:

    <xsl:stylesheet version='1.0' xmlns:xsl='http://www.w3.org/1999/XSL/Transform'> <xsl:output method='text'/>  <xsl:template match='*'>   <xsl:apply-templates select='@TEXT | node()'/> </xsl:template>  <xsl:template match='node/@TEXT | text()'>   <xsl:if test='normalize-space(.)'>     <xsl:value-of select=      'concat(normalize-space(.), '&#xA;')'/>   </xsl:if>    <xsl:apply-templates /> </xsl:template>  </xsl:stylesheet>

    when applied against this XML document

    <t> <node TEXT='   txt A   '/> <node TEXT='       txt X'/> <node>     <html>         <p>        txt Y      </p>     </html> </node> <node TEXT='txt B'/> </t>

    produces the wanted result:

    txt A
    txt X
    txt Y
    txt B

    Do note the use of the standard XPath function normalize-space(), which strips off all leading and trailing spaces and replaces every sequence of other spaces with just one space.

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