Home/ Questions/Q 7890675
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-06-03T06:25:03+00:00

I have something like this: <ul> <li>User</li> <li>Admin</li> .. </ul> and want to render

  • 0

I have something like this:

<ul>        
<li>User</li>
<li>Admin</li>
..
</ul>

and want to render the list-item ‘Admin’ only if the actual User is in Role ‘Admin’.

I know, I can do that like this:

<ul>        
<li>User</li>
<h:panelGroup rendered="#{request.isUserInRole('admin')}">
<li>Admin</li>
</h:panelGroup>
..
</ul>

However the markup inserts a “span”-element because of h:panelGroup.

Is there a JSF-Component with a ‘rendered’-property which does not insert any html?

Unfortunately, Facelets ui:remove/ui:include has not a ‘rendered’ property:

<ul>        
<li>User</li>
<ui:remove rendered="#{request.isUserInRole('admin')}">
<li>Admin</li>
</ui:remove>
..
</ul>

How should I solve such a scenario?

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    What you mean can be achieved by using ui:fragment.

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<ui:composition xmlns="http://www.w3.org/1999/xhtml"
                xmlns:ui="http://java.sun.com/jsf/facelets">

    <ui:fragment rendered="#{action.isUserLoggedIn()}">
        <!-- this will only be shown to logged in users -->
    </ui:fragment>
</ui:composition>
    • 0