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Editorial Team
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Asked: 2026-05-12T07:23:37+00:00

I have something simple like this: $(selector).append("somestuff"); But since I’m going to reuse the

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I have something simple like this:

$(selector).append("somestuff");

But since I’m going to reuse the selector I cache it with:

var $selector = $(selector);

So I end up with:

$selector.append("somestuff");

My question is, should I be doing that, or should I be doing:

var selector = $(selector);
selector.append("somestuff");

Trying either one, both works. Which method is correct, and why? Is the $ in $selector unnecessary because the jquery object has already been declared in $(selector)?

Edit

Thanks for the answers. It seems very simple and quite clear. Still, there seems to be disagreement over whether or not I should use $ in the variable. It would be nice for everyone to vote up an answer. 🙂

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1 Answer

  1. Editorial Team

    I’ve seen it done both ways. All you are doing is creating a variable with the name ‘$selector’, so they are functionally equivalent. The nice thing about it is that it does make them easy to pick out as jQuery objects.

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