Question

I have spent the past 6 hours trying to solve this ! and i coulnt get anywhere :s

I want to be able to create a lua table in a c++ file and then pass that to a lua script file, which has the following lua function:

function MTable (t) 
local n=#t
    for i=1,n do 
      print(t[i]) 
    end
end

i dynamically created a one dimensional array with two strings:

 lua_newtable(L);
 lua_pushstring(L,"10.10.1.1");
 lua_pushstring(L,"10.10.1.2");
 lua_rawseti(L,-3,2);
 lua_rawseti(L,-2,1);

so now i have the table on top of the stack.
I have verified it by writting this :
if( lua_istable(L,lua_gettop(L)))` which returned 1, which means it is a table.

then I did this:

lua_getglobal(L, "MTable");    // push the lua function onto the stack

uint32_t   result = lua_pcall(L, 1, 0, 0);  //argument 1 is for the table
 if (result) {
 printf(stderr, "Failed to run script: %s\n", lua_tostring(L, -1));
         exit(1);
}

so I got that error:
Failed to run script: attempt to call a table value

Kindly note that the file has several other functions that i am calling successfully from c++.

can somebody please help me solve this error ? can this be a bug from LUA? cz i followed the steps very correctly…i guess !

Answer 1

The function has to be first on the stack, before the args.

You can either:

1. push the function to call on the stack before generating the table, e.g.:

   lua_getglobal(L, "MTable");
   ...generate table on stack...
   int result = lua_pcall(L, 1, 0, 0);
   

2. Do in the order you do now, and then just swap the arg and the function prior to doing the pcall:

   ...generate table on stack...
   lua_getglobal(L, "MTable");
   lua_insert (L, -2);   // swap table and function into correct order for pcall
   int result = lua_pcall(L, 1, 0, 0);