Question

I have SQLite database and I have in it certain column of type ‘double’. I want to get a row that has in this column value closest to a specified one.

For example, in my table I have:

id: 1; value: 47 id: 2; value: 56 id: 3; value: 51 

And I want to get a row that has its value closest to 50. So I want to receive id: 3 (value = 51).

How can I achieve this goal?

Thanks.

Answer 1

This should work:

SELECT * FROM table ORDER BY ABS(? - value) LIMIT 1 

Where ? represents the value you want to compare against.