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Home/ Questions/Q 839677
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T05:30:16+00:00 2026-05-15T05:30:16+00:00

I have strings like 5d4h2s, where I want to get 5, 4, and 2

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I have strings like “5d4h2s”, where I want to get 5, 4, and 2 from that string, but I also want to know that 5 was paired with d, and that 4 was paired with h, etc etc. Is there an easy way of doing this without parsing char by char?

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  1. Editorial Team
    Editorial Team
    2026-05-15T05:30:17+00:00Added an answer on May 15, 2026 at 5:30 am

    If your input does not get more complicated than 5d4h2s:

    >>> import re
    >>> s = "5d4h2s"
    >>> p = re.compile("([0-9])([a-z])")
    >>> for m in p.findall(s):
    ...   print m
    ... 
    ('5', 'd')
    ('4', 'h')
    ('2', 's')
    

    And if it gets, you can easily adjust the regular expression, e.g.

    >>> p = re.compile("([0-9]*)([a-z])")
    

    to accept input like:

    >>> s = "5d14h2s"
    

    Finally, you can condense the regex to:

    >>> p = re.compile("([\d]+)([dhms])")
    
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