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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T20:05:32+00:00 2026-05-15T20:05:32+00:00

I have structure for storing callback function like this: template<class T> struct CommandGlobal :

  • 0

I have structure for storing callback function like this:

template<class T>
struct CommandGlobal : CommandBase
{
    typedef boost::function<T ()> Command;
    Command comm;

    virtual T Execute() const
    {
        if(comm)
            return comm();
        return NULL;
    }
};

Seems like it should work fine except when T is void because the Execute function wants to return a value..

What is the best solution to this problem?

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  1. Editorial Team
    Editorial Team
    2026-05-15T20:05:33+00:00Added an answer on May 15, 2026 at 8:05 pm

    This answer is based off this fun-fact: In a function returning void, you can return any expression of which the type is void.

    So the simple solution is:

    virtual T Execute() const
    {
        if (comm) 
            return comm();
        else
            return static_cast<T>(NULL);
    }
    

    When T = void, the last return statement is equivalent to return;.


    However, I feel this is bad design. Is NULL meaningful for every T? I don’t think so. I would throw an exception:

    virtual T Execute() const
    {
        if (comm)
            return comm();
        else
            throw std::runtime_error("No function!")
    }
    

    However, this is done automatically by Boost, so your code becomes the much cleaner:

    virtual T Execute() const
    {
        return comm();
    }
    

    You could then add additional functionality, such as:

    bool empty(void) const
    {
        return !comm; // or return comm.empty() if you're the explicit type
    }
    

    So the user can check if it can be called prior to calling it. Of course at this point, unless your class has additional functionality you’ve left out for the sake of the question, I see no reason not to just use boost::function in the first place.

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