i have successfully added input element into div, which looks like this :
$(document).ready(function() {
$('#jumlah').change(function() {
var jum = $('#jumlah').val();
for(i=1;i<=jum; i++){
$('#jawaban').append('<label>Jawaban Soal ' + i + ' : </label><input type="text" name="jawab'+i+'" id="jawab[]" size="2" maxlength="1" /><br>');
}
});
});
and some my HTML codes are :
<select name="jumlah" id="jumlah" class="test">
<option value="0" selected="selected">choose value</option>
<?php
for($i=1;$i<=20;$i++)
echo("<option value=\"$i\">$i</option>");
?>
</select>
<div id="jawaban"></div>
but when i choose different value, it appends more input elements under the first ones, for example, if i choose option 2 and then option 3 it will look like :
Jawaban Soal 1 : <input />
Jawaban Soal 2 : <input />
Jawaban Soal 1 : <input />
Jawaban Soal 2 : <input />
Jawaban Soal 3 : <input />
Please help, i’m still junior in Jquery. I’m looking forward to your respond.
I’m guessing you want the old ones to disappear, in which case you should empty the
jawabandiv first.You (infact a considerable amount of people), should cache the jQuery objects you build. Each time you use
$('someSelector')in your code, jQuery re-selects your elements, and returns a new object for you each time. this is none trivial!