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Home/ Questions/Q 6689091
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T05:28:44+00:00 2026-05-26T05:28:44+00:00

I have such postresql query: SELECT * , u.image AS image_name, k.id AS cat_id,

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I have such postresql query:

SELECT * , u.image AS image_name, k.id AS cat_id,
   CASE WHEN s.web_site!="" THEN s.web_site
   ELSE 'Not available' END AS v_site
FROM users u
LEFT JOIN comments s ON s.user_id = u.id WHERE u.id = '1547'

Query result:

users     | name    | v_site
----------+---------+---------------
ali       | hassan  | www.domain.com
turqut    | sandra  | www.somesite.com
emil      | azizov  | www.website.com

As u see I get website name like that http://www.domain.com. But I want to get that with HTML hyperlink tag: <a href=’www.domain.com’>www.domain.com
</a>

How can I do that?

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  1. Editorial Team
    Editorial Team
    2026-05-26T05:28:44+00:00Added an answer on May 26, 2026 at 5:28 am

    != "" is invalid SQL syntax. Strings are delimited with a single qutoe.

    SELECT *, 
           u.image AS image_name, 
           k.id AS cat_id,
           CASE 
             WHEN s.web_site != '' THEN '<a href="'||s.web_site||'">'||s.web_site||'</a>'
             ELSE 'Not available' 
           END AS v_site
    FROM users u
    LEFT JOIN comments s ON s.user_id = u.id WHERE u.id = '1547'
    
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