Question

I have table data like this

id id1  name
1  1    test1
1  1    test1
1  2    test2
2  1    test1
2  2    test2
3  1    test1
3  2    test2
3  2    test2

now from table i want the data as below
like
for id = 1 order by id1 asc the first name = test1
so i want the first two row

id id1  name
1  1    test1
1  1    test1

not third row

For id=2 order by id1 asc the first name = test1
so i want first row as test1 has assign only ones for id=2

id id1  name
2  1    test1

And for id=3 same as id=2

Please suggest me how can get the perticlur value for ID , because the scenerio is differnt for ID=1

Answer 1

Use RANK() or DENSE_RANK() to get the first ranked rows, including duplicates, for each id.

select * from (
    select *, dense_rank() over (partition by [id] order by [id2]) as ranking
    from [table]
) as t
where ranking = 1