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Home/ Questions/Q 6602751
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T18:54:49+00:00 2026-05-25T18:54:49+00:00

I have table like this id | type — —– 1 | fh —

  • 0

I have table like this

id | type 
--- ----- 
1  | fh  
--- ----- 
2  | fhs  
--- -----  
3  | so    
--- -----  
4  | sos   


while($row = mysql_fetch_array($res)){
    if($row['type'] == "fh" OR $row['type'] == "fhs"){
        $name = "Flush Head Studs";
    }else if($row['type'] == "so" OR $row['type'] == "sos"){
        $name = "Through Standoffs";
    }
    $category .= '<option value="'.$row['type'].'" name="'.$row['type'].'">' . $name . '</option>';
}

code above is displayng names twice. How can i do that names are only once in list.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T18:54:50+00:00Added an answer on May 25, 2026 at 6:54 pm

    your result is correct! if you change your code like this, you can see why …

    while($row = mysql_fetch_array($res)){
        if($row['type'] == "fh" OR $row['type'] == "fhs"){
            $name = "Flush Head Studs ".$row['type'];
        }else if($row['type'] == "so" OR $row['type'] == "sos"){
            $name = "Through Standoffs ".$row['type'];
        }
        $category .= '<option value="'.$row['type'].'" name="'.$row['type'].'">' . $name . '</option>';
    }
    

    if you want select all types, i suggest you to add a description or name column to your table … because you youse all of your types as value in the select-field.

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