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Home/ Questions/Q 6385625
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T02:55:24+00:00 2026-05-25T02:55:24+00:00

I have table with Doctrine: Name: columns: name_id: { type: integer(11), primary: true, autoincrement:

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I have table with Doctrine:

Name:
  columns:
    name_id: { type: integer(11),  primary: true,  autoincrement: true }
    name_name: { type: string(65)}
    parent_name_id: { type: integer(11) }

If i edit Name i would like in input parent_name_id list select with name_id, added previous.
I would like use:

NameTable.class.php:

  static public $name = array(
    'full-time' => 'Full time', //  foreach ???
    'part-time' => 'Part time', // ????
    'freelance' => 'Freelance'  // ????
  );

  public function getName()
  {
    return self::$name;
  }

and

$this->widgetSchema['parent_name_id'] = new sfWidgetFormChoice(array(
  'choices'  => Doctrine::getTable('Name')->getName(),
  'expanded' => true,
));

but how can i generated this in model?

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  1. Editorial Team
    Editorial Team
    2026-05-25T02:55:25+00:00Added an answer on May 25, 2026 at 2:55 am
    Name:
      columns:
        name_id: { type: integer(11),  primary: true,  autoincrement: true }
        name_name: { type: string(65)}
        parent_name_id: { type: integer(11) }
    
    1. Why name_name ? It will be good, rename it for name 🙂
      Than you make:

    $ php symfony doctrine:build –all –and-load –no-confirmation

    and in /lib/model/doctrine/base in BaseName.class.php you can see all generated method, for example

    * @method string              getName()                Returns the current record's "name" value
    

    You can use sfWidgetFormDoctrineChoice

    For example:

    $this->widgetSchema['parent_name_id'] = new sfWidgetFormDoctrineChoice('model' => 'Name', 'add_empty' => false, 'multiple' => false);
    
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