Question

I have table with name users and a column in it named source . The column contains 3 different type of values which are strings(facebook, google, yahoo). Now I need to count how many Facebook strings, google strings & yahoo strings are present in that column.

Any easy simple way to do it using php query?

How do I get to display the number!!!!!!!!

Answer 1

You can use this solution. This gets the counts into separate columns so you can easily reference to the count of your different strings in php:

SELECT
    COUNT(CASE WHEN source = 'facebook' THEN 1 END) AS facebook_count,
    COUNT(CASE WHEN source = 'google' THEN 1 END) AS google_count,
    COUNT(CASE WHEN source = 'yahoo' THEN 1 END) AS yahoo_count
FROM
    users

Edit: As per your comments to this answer… On how to retrieve these values using php, something like this:

$sql = "
    SELECT
        COUNT(CASE WHEN source = 'facebook' THEN 1 END) AS facebook_count,
        COUNT(CASE WHEN source = 'google' THEN 1 END) AS google_count,
        COUNT(CASE WHEN source = 'yahoo' THEN 1 END) AS yahoo_count
    FROM
        users";

$social = mysql_query($sql);

while($row = mysql_fetch_assoc($social))
{
    echo "FB Count: {$row['facebook_count']}" . '<br />';
    echo "Google Count: {$row['google_count']}" . '<br />';
    echo "Yahoo Count: {$row['yahoo_count']}";
}