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Editorial Team
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Asked: 2026-05-26T19:18:13+00:00

I have table with some events and their dates in a mysql database and

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I have table with some events and their dates in a mysql database and I wanna return a counting of the events per weekday like this:

SELECT DAYNAME(start_date) AS day, count(DAYNAME(start_date)) as number FROM events GROUP BY day

That works great for days in which occur some events, but it doesn’t show the empty days. I know if I would have a simple table with days of the week I could do a simple LEFT JOIN and show ALL days, with a count = 0 when the day is empty. But is there any simpler way to do that without creating that table? Any other ideas?

Thanks in advance

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1 Answer

  1. Editorial Team

    In a word ‘no’. Reason being that you are trying to select data that does not exist!

    However, since there are only 7 days in a week you could construct your simple ‘Days Of The Week’ table on the fly:

    select dayname('2011-10-31') union
select dayname('2011-11-01') union
select dayname('2011-11-02') union
select dayname('2011-11-03') union
select dayname('2011-11-04') union
select dayname('2011-11-05') union
select dayname('2011-11-06');

    And then LEFT OUTER JOIN from that onto the events table (as you have described). This will allow you to run a query without having to create and populate the simple table.

    Though for the sake of reuse and tidiness I would create and populate the simple table with days of the week and use that.

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