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Home/ Questions/Q 5980425
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T21:47:55+00:00 2026-05-22T21:47:55+00:00

I have: <td data-X=1,2> and when I do: var Y = $(‘td’).data(‘X’); Z=Y.split(); it

  • 0

I have:

<td data-X="1,2">

and when I do:

var Y = $('td').data('X');
Z=Y.split();

it works.

But if I have:

<td data-X="1">

then it doesn’t work.
At least I think that’s what’s happening. I’m getting “Y.split is not a function”, but only sometimes.

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  1. Editorial Team
    Editorial Team
    2026-05-22T21:47:56+00:00Added an answer on May 22, 2026 at 9:47 pm

    .data() is smart. It tries to use a more appropriate type than string for the value – in your case, it’s number.

    From the docs:

    Every attempt is made to convert the string to a JavaScript value (this includes booleans, numbers, objects, arrays, and null) otherwise it is left as a string. To retrieve the value’s attribute as a string without any attempt to convert it, use the attr() method.

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