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Home/ Questions/Q 7779521
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T18:39:34+00:00 2026-06-01T18:39:34+00:00

I have template <void (*T)(Entity *), typename Caller> class Updater { public: Updater(Caller c):m_caller(c){}

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I have

template <void (*T)(Entity *), typename Caller>
class Updater 
{
public:
    Updater(Caller c):m_caller(c){}
    void process(Entity * e)
    {
        (m_caller->*T)(e);              //Is this right?
    }
private:
    Caller m_caller;
};

I understand I can instantiate it like

Foo f;
Updater<&Foo::Bar> updater(&f);

assuming that Foo has

void Foo::Bar(Entity *e);

but what if it has desired method tempated? Like this

template <typename T>
void Bar(T t);

how shoult I instanciate it? Like this:?

Foo f;
Updater<&Foo::Bar<Entity *>> updater(&f);

When I do this in my real code, I get

invalid template argument for ..., expected compile-time constant expression

So 2 questions:

1, is (m_caller->*T)(e); correct? If it is not, how shout i call it?

2, how can I instantiate it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T18:39:35+00:00Added an answer on June 1, 2026 at 6:39 pm
    template <typename Caller, void (Caller::*Func)(Entity *)>
    class Updater 
    {
    public:
        Updater(Caller *c):m_caller(c){}
        void process(Entity * e)
        {
            (m_caller->*Func)(e); // use pointer to member operator ->*
        }
    private:
        Caller *m_caller;
    };
    
    // call like this
    Foo f;
    Updater<Foo, &Foo::Bar> updater(&f);
    
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