Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 882229
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T12:23:45+00:00 2026-05-15T12:23:45+00:00

i have tested following code which might print 0 and 2 but it print

  • 0

i have tested following code which might print 0 and 2 but it print 1 and 1 why?

public class break_command {


    public static void main(String[] args) {
       for (int i=0;i<10;i++){
            for (int j=1;j<10;i++){
                if ((i+j) %2==0){
                    System.out.println("i  "+ i +"  j   " +j);
                    break;
                }


            }
            break;
       }
    }

}

result//
i  1  j   1
BUILD SUCCESSFUL (total time: 0 seconds)
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T12:23:46+00:00Added an answer on May 15, 2026 at 12:23 pm

    Is the line:

    for (int j=1;j<10;i++){
    

    Supposed to be j++ not i++?

    Otherwise it means on the first iteration:

    if ((i+j) %2==0){
    

    Will be true.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have the following regular expression: [0-9]{8}.*\n.*\n.*\n.*\n.* Which I have tested in Expresso against
I have a JList component which should be emptied and repopulated. The following code
I have the following code, which I am using to test how I'm using
I have the following UDP broadcast listener running as a static component in a
In windows XP, python 2.5 and 2.6 I tested the following code: import urllib2
Please, consider the following (I'm sorry for the amount of code; but this is
i have a input tag which is non editable, but some times i need
I have the following code on an html page: <script type=text/javascript> <!-- window.location.replace(http://www.example.com/); -->
I tested the following code in Racket/DrScheme: (define (makem) (define x 34) (list (lambda
This is a bit maddening. I have code which saves the current background-image from

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.