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Asked: 2026-06-03T07:18:22+00:00

I have the above shell script . #!/bin/bash # a shell script that keeps

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I have the above shell script .

#!/bin/bash

# a shell script that keeps looping until an exit code is given

nice php -q -f ./data.php -- $@
ERR=$?

exec $0 $@

I have a few doubts

  1. What is $0 and what is $@
  2. what is ERR=$?
  3. what does -- $@ in 5th line do
  4. I wanted to know if can i pass data.php as a parameter. so that i have only i shell script for all kind of execution . Say, i want to run “sh ss.sh data1.php” then this should run data1.php, if run “ss ss.sh data2.php” it should run data2.php –
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1 Answer

  1. Editorial Team

    1) $0 is the name of the executable (the script in your case, eg: if your script is called start_me then $0 is start_me)

    2) ERR=$? gets the return code of nice php -q -f ./data.php -- $@

    3) -- $@ does two things, first of all it tell the php command that all following parameter shall be passed to data.php and $@ passes all given parameter to the script to ./data.php (eg. ./your_script_name foo bar will translate to nice php -q -f ./data.php -- foo bar)

    4) short answer yes, but you have to change the script to

     YOUR_FILE=$1
 shift #this removes the first argument from $@
 nice php -q -f ./$YOUR_FILE -- $@
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