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Home/ Questions/Q 8801251
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Editorial Team
  • 0
Editorial Team
Asked: June 14, 20262026-06-14T00:47:15+00:00 2026-06-14T00:47:15+00:00

I have the below code. (function($) { var myFunction = function(element) { var myCallerFunction

  • 0

I have the below code.

(function($) {

    var myFunction = function(element) {

        var myCallerFunction = function() {
            var functionName = 'myInternalCallFunction';
            myFunction[functionName]();
            console.log(2);

        }

        var myInternalCallFunction = function() {

            console.log(1);
        }

        myCallerFunction();

    }

    $.fn.myfunction = function(options) {
        var func = new myFunction();
    }

})(jQuery);

Inside myCallerFunction I created a variable which holds the function name I want to call. I then try to call it, however it returns that it can’t find the function. It finds the namespace myFunction okay as if I change:

myFunction[functionName]();

to

myFunctionTest[functionName]();

It returns it can’t find “myFunctionTest” instead of not being able to find “myInterncalCallFunction”.

Any ideas why it can’t find the function?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T00:47:16+00:00Added an answer on June 14, 2026 at 12:47 am

    By calling myFunction['myInternalCallFunction']() you are actually calling myFunction.myInternalCallFunction(). Of course, it is undefined since myInternalCallFunction is not a property of myFunction, it is its private variable. One way of solving this while not turning private variables to properties:

    (function($) {
    
        var myFunction = function(element) {
            var cache = {};
            var myCallerFunction = function() {
                var functionName = 'myInternalCallFunction';
                cache[functionName]();
                console.log(2);
    
            }
    
            cache.myInternalCallFunction = function() {
    
                console.log(1);
            }
    
            myCallerFunction();
    
        }
    
        $.fn.myfunction = function(options) {
            var func = new myFunction();
        }
    
    })(jQuery);
    
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