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Home/ Questions/Q 7550067
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T10:07:05+00:00 2026-05-30T10:07:05+00:00

I have the below code. I can’t make it work. I have to mention

  • 0

I have the below code. I can’t make it work.

I have to mention that the URL is redirecting. I mean that url = http://www.thissite.com and redirects to http://www.othersite.com. But I want to get it work with the initial url.

 public void download(String address, String localFileName, JProgressBar progress ) {
    OutputStream out = null;
    URLConnection conn = null;
    InputStream in = null;

    try {

          URL url = new URL(address);



        // Open an output stream to the destination file on our local filesystem
        out = new BufferedOutputStream(new FileOutputStream("/MusicDownloads/"+localFileName));
        conn = url.openConnection();

        in = conn.getInputStream();

        int length = conn.getContentLength(); //find out how long the file is, any good webserver should provide this info
         int current = 0;
          progress.setMaximum(length); //we're going to get this many bytes
          progress.setValue(0); //we've gotten 0 bytes so far

        // Get the data
        byte[] buffer = new byte[1024];
        int numRead = 0;

        while ((numRead = in.read(buffer)) != -1) {
            current=0;
            out.write(buffer, current, numRead);

              current += numRead; //we've progressed a little so update current

            progress.setValue(current); //tell progress how far we are


        }
        // Done! Just clean up and get out
    } catch (Exception exception) {
        exception.printStackTrace();
    } finally {
        try {
            if (in != null) {
                in.close();
            }
            if (out != null) {
                out.close();
            }
        } catch (IOException ioe) {
            // Shouldn't happen, maybe add some logging here if you are not
            // fooling around ;)
        }
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-30T10:07:06+00:00Added an answer on May 30, 2026 at 10:07 am

    Use a ProgressMonitorInputStream instead.

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