Question

I have the below code that allows a user to write in a executable (i.e. notepad.exe) and then clicking the start button it will start the process.

However, how do I make the TextBox accept enter/return key? I put in AcceptsReturn=true but it is not doing anything. I have also set in Visual Studio the property Accept Return = True – still nothing.

using System;
using System.Diagnostics;
using System.Windows.Forms;

namespace process_list
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            string text = textBox1.Text;
            Process process = new Process();
            process.StartInfo.FileName = text;
            process.Start();
        }

        private void textBox1_TextChanged(object sender, EventArgs e)
        {
            textBox1.AcceptsReturn = true;
        }
    }
}

Answer 1

Set the AcceptButton of the form to your button. You don’t need AcceptsReturn then, because Enter automatically triggers the button.

public Form1()
{
    InitializeComponent();
    this.AcceptButton = button1;
}