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Home/ Questions/Q 6704519
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T07:17:53+00:00 2026-05-26T07:17:53+00:00

I have the below if statement. It gives me syntax error when I have

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I have the below if statement. It gives me syntax error when I have both the csv file and the zip file in the folder. But it works when I have the csv file alone or the zip file alone or no files exist.

I’m not sure what causes the syntax error in the command below:

if [ -f ctf_error_report_??_????????????.csv -o -f ctf_error_report_??_????????????.???.zip ];
then
     echo  "Successful"
else
     echo  "Problem"
fi
exit 0

Any insight regarding this?

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  1. Editorial Team
    Editorial Team
    2026-05-26T07:17:54+00:00Added an answer on May 26, 2026 at 7:17 am

    This is a dangerous way to check for files. If you happen to have more than one match in that directory then it won’t work because each file will become a separate parameter, which won’t match the syntax of the text. A better (although not foolproof) way to do it is like this:

    set ctf_error_report_??_????????????.csv
    csv_file=$1
    set ctf_error_report_??_????????????.???.zip
    zip_file=$1
    
    if [ -f "$csv_file" -o -f "$zip_file" ]
    then
      echo  "Successful"
    else
      echo  "Problem"
    fi
    
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