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Editorial Team
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Asked: 2026-05-27T13:00:44+00:00

I have the below (simplified) code, which uses the following source: <html> <p>line 1</p>

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I have the below (simplified) code, which uses the following source:

<html>
    <p>line 1</p>
    <div>
        <a>line 2</a>
    </div>
</html>

soup = BeautifulSoup('<html><p>line 1</p><div><a>line 2</a></div></html>')
ele = soup.find('p').nextSibling
somehow_print_tag_of_ele_here

I want to get the tag of ele, in this case “div”. However, I only seem to be able to get the tag of its children. Am I missing something simple? I thought that I could do ele.tag.name, but that is an exception since tag is None.

#Below correctly prints the div element "<div><a>line 2</a></div>"
print ele

#Below prints "None". Printing tag.name is an exception since tag is None
print ele.tag 

#Below prints "a", the child of ele
allTags = ele.findAll(True)
for e in allTags:
    print e.name

At this point, I am considering doing something along the way of getting the parent of ele, then getting the tags of parent’s children and, having counted how many upper siblings ele has, counting down to the correct child tag. That seems ridiculous.

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1 Answer

  1. Editorial Team

    ele is already a tag, try doing this:

    soup = BeautifulSoup('<html><p>line 1</p><div><a>line 2</a></div></html>')
print(soup.find('p').nextSibling.name)

    So in your example it would be just

    print(ele.name)
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