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Home/ Questions/Q 6829995
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T22:33:57+00:00 2026-05-26T22:33:57+00:00

I have the below table in a .JSP page: <form:form method=post action=update.dtt id=contactForms modelAttribute=contactForms

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I have the below table in a .JSP page:

<form:form method="post" action="update.dtt" id="contactForms" modelAttribute="contactForms" >
<c:forEach items="${pList}" var="cf">
<tr>
<td align="center"><c:out value="${cf.fname}" /></td>
<td align="center"><c:out value="${cf.lname}" /></td>
<td align="center"><c:out value="${cf.cprovider}" /></td>
<td align="center"><c:out value="${cf.id}" /></td>
<td align="center"><c:out value="${cf.phone}" /></td>
<td><input type="submit" value="Update Contact"/></td>
</tr>
</c:forEach>
</form:form>

I’m iterating over the list (this is list of objects) and adding an Update Contact button for each record in the list. How can I pass on the particular instance (object) to the controller when the Update button is clicked?

The controller I have is as below. However I’m getting null.

@RequestMapping(value = "/user/update.dtt", method = RequestMethod.POST)
public String updateView(@ModelAttribute("contactForms") Banks bank,      HttpServletRequest request, HttpServletResponse response, Model model) {

    System.out.println("*First Name*" + bank.getFname());
//......

    return "detailBank"; //name of jsp file
}
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  1. Editorial Team
    Editorial Team
    2026-05-26T22:33:58+00:00Added an answer on May 26, 2026 at 10:33 pm

    You’ll need to have a hidden form field for each information you want to send to the server.

    Since you have one button for each row, you should also have one form for each row. So the <form:form> and </form:form> lines should be inside the <c:forEach>, and not outside.

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