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Home/ Questions/Q 6971091
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T16:47:40+00:00 2026-05-27T16:47:40+00:00

I have the byte array of the RSA Public Key. I found on the

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I have the byte array of the RSA Public Key. I found on the internet that I can create a real PublicKey object of it by using this code:

PublicKey publicKey = 
    KeyFactory.getInstance("RSA").generatePublic(new X509EncodedKeySpec(bytes));

But every time I run this code, I’m getting another result for the encrypted data using that key. I’m sure the data I want to encrypt is always the same, so does the byte array representing the key.

Is this normal?

Here is my code always producing another output:

byte[] keyBytes = Base64.decodeBase64(rsa_1024_public_key);
      // rsa_1024_public key is a constant String

Cipher c = Cipher.getInstance("RSA");

PublicKey publicKey =
   KeyFactory.getInstance("RSA").generatePublic(new X509EncodedKeySpec(keyBytes));

c.init(Cipher.ENCRYPT_MODE, publicKey);

return c.doFinal(password.getBytes());

This is probably a part of the asymmetric encryption algorithm?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-27T16:47:40+00:00Added an answer on May 27, 2026 at 4:47 pm

    RSA is non-determinstic.

    You can make it deterministic by selecting a non-random padding mode; however, that will not be secure.

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