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Home/ Questions/Q 8745727
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T12:04:50+00:00 2026-06-13T12:04:50+00:00

I have the code as below: <tr> <td>Date :</td> <td><input type=text name=txtdembauche value=<?php echo

  • 0

I have the code as below:

<tr>
  <td>Date :</td>
  <td><input type="text" name="txtdembauche" value="<?php echo $value['dateEmbouche'] ?>"class="validate[required] text-input datepicker TextInput"  id="txtdembauche"/></td>
  <td></td>
</tr>
<?php                           

  @$date1 = $_POST['txtdembauche'];
  $date2 = date("Y-m-d");
  $diff = abs(strtotime($date2) - strtotime($date1));
  $years = floor($diff / (365*60*60*24));
  $months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
  $days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));     

?>
<tr>
  <td>Ancienneté : <b id="anciente" style="color:#FF0000;"><?php printf("%d years, %d months, %d days\n <br />", $years, $months, $days); ?></b></td>
  <td></td>
  <td></td>
</tr>
<input type="text" name="dateResult" id="dateResult" value="<?php // I do not know how to calculate this ?>">

Problem:

<tr>
  <td>Ancienneté : <b id="anciente" style="color:#FF0000;"><?php printf("%d years, %d months, %d days\n <br />", $years, $months, $days); ?></b></td>
  <td></td>
  <td></td>
</tr> 

It not works well,it display the wrong date.

<input type="text" name="dateResult" id="dateResult" value="<?php // I do not know how to calculate this ?>">

I want to get the age of person between date and date now ex: 12years, but I do not know how to do this.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T12:04:51+00:00Added an answer on June 13, 2026 at 12:04 pm

    As for comments this is something about your coding technique or the concept. I have created a test code just follow it and identify where you went wrong

    <?php                           
    if(isset($_POST['submit'])){
      @$date1 = $_POST['txtdembauche'];// if format mm/dd/yyyy
      $date2 = date("m/d/Y");//change m,d,y according to input data format
      $diff = abs(strtotime($date2) - strtotime($date1));
      $years = floor($diff / (365*60*60*24));
      $months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
      $days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));     
    }
    ?>
    <form action="" method="post">
    <table>
    <tr>
      <td>Date :</td>
      <td><input type="text" name="txtdembauche" value="<?php echo $value['dateEmbouche'] ?>"class="validate[required] text-input datepicker TextInput"  id="txtdembauche"/></td>
      <td><input type="submit" name="submit" value="Get Age"></td>
    </tr>
    <tr>
      <td>Ancienneté : </td>
       <td><b id="anciente" style="color:#FF0000;"><?php printf("%d years, %d months, %d days\n <br />", $years, $months, $days); ?></b></td>
      <td></td>
    </tr>
    <tr>
      <td>Age</td>
      <td><input type="text" name="dateResult" id="dateResult" value="<?php echo $years; ?>"></td>
      <td></td>
    </tr>
    </table>
    </form>
    
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