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Home/ Questions/Q 6251021
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T13:32:14+00:00 2026-05-24T13:32:14+00:00

I have the code below and it’s working as it should however instead of

  • 0

I have the code below and it’s working as it should however instead of echoing the results to the screen, I need to store the results in a php variable called $var. How would I go about doing that?

<?php
$sql = "SELECT id_member FROM smf_members WHERE FIND_IN_SET(24,additional_groups)";

$con = mysql_connect('localhost', 'sqluser', 'sqlpass');
if (!$con) {
   die('Could not connect: ' . mysql_error());
}

mysql_select_db("test_db");
$result = mysql_query($sql, $con);

while ($row = mysql_fetch_array($result)) {
   echo $row['id_member'];
}

mysql_close($con);
?>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T13:32:14+00:00Added an answer on May 24, 2026 at 1:32 pm

    Depending on what you want to achieve here is a few possible ways of doing this

    $var = "";
    
    while ($row = mysql_fetch_array($result)) {
      $var .= $row['id_member'] . "\n";
    }
    
    $var = array();
    
    while ($row = mysql_fetch_array($result)) {
      $var[] = $row['id_member'];
    }
    
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