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Home/ Questions/Q 699739
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T03:25:09+00:00 2026-05-14T03:25:09+00:00

I have the code: unsigned int length = strlen(somestring); I’m compiling with the warning

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I have the code:

unsigned int length = strlen(somestring);

I’m compiling with the warning level on 4, and it’s telling me that “conversion from size_t to unsigned int, possible loss of data” when a size_t is a typedef for an unsigned int.

Why!?

Edit:

I just solved my own problem. I’m an XP user, and my compiler was checking for 64 bit compatibility. Since size_t is platform dependent, for 64 bit it would be an unsigned long long, where that is not the same as an unsigned int.

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  1. Editorial Team
    Editorial Team
    2026-05-14T03:25:10+00:00Added an answer on May 14, 2026 at 3:25 am

    Because unsigned int is a narrower type on your machine than size_t. Most likely size_t is 64 bits wide, while unsigned int is 32 bits wide.

    EDIT: size_t is not a typedef for unsigned int.

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